# Waec Physics Pasword Page

Friday 28th August 2020

Physics 2 (Essay) – 9:30am –11:00am

Physics 1 (objective) – 11:00am –12:15pm

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PHYSICS OBJ

1-10: DCCAACDCCC

11-20: BDBABBDCCB

21-30: ACBACCCBAD

31-40: BDDBDACCCA

41-50: CAAABBCBBC

__SECTION A __

__(Answer ONLY FIVE Questions from this Section__

(1)

Original length Lo = 3m

extension e = 3Lo = 3×3 = 9m

F ∝e

F = ke where k = 982.3Nm‐²

F = 982.3×9 = 8840.7N

The force that produces the extension F = 8840.7N

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(2a)

Metal flat plate: It is a collector of heat that converts the radiant solar energy from the sun into heat energy by the process of greenhouse effect.

(2b)

Thermal Insulator: It prevents loss of accumulated heat in the solar collector and thereby improves its absorption efficiency.

(2c)

Tubes: They are use to capture almost all the sun’s energy. It is the most efficient solar collector

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(3a)

Plastic

(3b)

The refractive index of the core must be greater than that of the cladding.

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( 4)

V ∝ T^x U^y

LT‐¹ ∝(MLT^‐²)^x(ML^‐1)^y

LT‐¹ ∝ M^xL^xT^‐²x × M^yL^-y

LT‐¹ ∝ M^(x+y) L^(x-y) T^‐²x

Comparing

X-y = 1 —–(1)

X+y = 0 —–(2)

-2x = -1 —-(3)

From equation 3,

X = 1/2

Putting X = 1/2 into eqn 2

y = -1/2

Equation is:

V ∝ T½ U‐½

V = √T/U

V = K√T/U

Where k is constant

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(5)

Work done in a gravitational field = force × distance

= f × r

= GMeM/R² × R

= GMeM/R

Work done is also kinetic energy, K.E = 1/2MVe²

Equating both

GMeM/R = 1/2MVe²

Ve² = 2GMe

Ve = √2GMe/R —–(1)

Also,Force f = GMeM/R² = mg

Me = gR²/G —–(2)

Putting (2) into (1)

Ve = √2GgR²/GR = √2gR

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(6)

θ = 30°, g = 10m/s²

Time of flight, T = 25seconds

Using,

Time of flight, T = 2usinθ/g

25 = 2usin30°/10

2u(0.5) = 250

u = 250

Velocity of projection, u = 250m/s

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__SECTION B __

__(Answer ONLY THREE Questions from this Section__

(8ai)

A torque is defined as a measure of the force that can cause an object to rotate about an axis

(8aii)

Factors that determine torque are;

– The magnitude of the force

– The radius

– The angle between the force and the lever arm

(8bi)

Free fall simply means the act of which are objects fall freely under the influence of gravitational force. An object under free fall does not encounter air resistance

(8bii)

Height of tower H = 40.0m

Velocity v = 10.0m/s, time t= ? , g=10.0m/s

Using the relation

S= ut + 1/2gt^2

H= ut + 1/2gt^2

40= 10t + 1/2*10t^2

4= t + t^2/2

= t^2 + 2t – 8=0 ( solving quadratically)

= (t+4)(t-2)=0

t+4=0 or t-2=0

t= -4 or t=2

Therefore time to fall on the ground t=2s

(8c)

Side of cube of wood = 8.0cm

2.0cm = 1/4 of the side immersed in water

R.density of water Rw = 1.00

R.density of Oil = Ro = 0.72

Volume of the wood V = L³

= 8×8×8

V = 512cm³

Volume immersed in water = 1/4×512 = 128cm³

Weight of water displaced = 128g × Rwater = 128×l

By applying the principle of flotation

Mass of wood = 128×Rw

=128 × l = 128g

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(10ai)

Critical angle is defined as the angle of incidence in the denser medium when the angle of refraction in the dense medium is 90°

(10aii)

The conditions necessary for total internal reflection to occur

1. Light must be traveling from an optically more dense to an optically less dense medium.

2. The angle of incidence in the denser medium must be greater than the critical angle.

(10aiii)

Three practical applications of total internal reflection:

[Choose three]

(i) Mirages

(ii) Field of view of a fish under water.

(iii) Refractometer.

(iv) Optical fibre.

(v) Binoculars.

(10b)

Two effects of refraction:

(i) Apparent depth of a swimming pool.

(ii) Apparent bending of a stick partly immersed in water.

(10ci)

Progressive wave is defined as a wave that transfers energy in traveling or moving away from the source of the disturbance.

(10cii)

y = 0.5sin(1000πt – 100πx)/17 = y = Asin(2πx/λ – wt)

(∝) at = 1000πt

===》 w = 1000

But w = 2πf

2πf = 1000π

f = 1000/2

f = 500Hz

(β) 2πx/λ = 100π/17 x

2/λ = 100/17

λ = 2×17/100

=0.34m

(γ) V = fλ

= 500 × 0.34

=170m/s

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